Why does solar intensity drop to only 4% at Jupiter compared to Earth?
Answer
The power density of sunlight decreases according to the inverse-square law.
The reduction in solar intensity experienced by spacecraft traveling away from the Sun is governed by the inverse-square law. This physical principle dictates that the intensity of radiant energy, such as sunlight, decreases proportionally to the square of the distance from the source. Consequently, by the time a probe reaches the orbital distance of Jupiter, the sunlight available is drastically reduced, amounting to only about four percent of the intensity measured at Earth's location. This rapid drop-off makes relying solely on photovoltaic cells impractical for missions destined for the outer solar system.

Related Questions
Why does solar intensity drop to only 4% at Jupiter compared to Earth?How do Radioisotope Thermoelectric Generators (RTGs) generate electrical energy?What is the specific, non-power generating role of a Radioisotope Heater Unit (RHU)?What dictates the necessity for nuclear power over solar arrays for deep-space probes?How do Space Nuclear Reactors based on fission compare to RTGs in power generation capability?Which challenge necessitates developing small, modular fission reactors for lunar surface operations?What advantage does Space Nuclear Propulsion offer for deep-space human travel?Why are regulations stringent regarding launching fissile material near Earth's vicinity?For which category of missions is nuclear power considered a fundamental requirement rather than an option?What characteristic makes RTGs ideal for long-duration missions like Voyager 1 and 2 or Cassini?