Why must the circumnavigation of UY Scuti be treated as a purely geometric calculation of its photosphere perimeter?
Answer
A stable, Earth-like object of this size is physically implausible due to self-gravity
Due to its immense size, a stable structure resembling an Earth-like object would be physically implausible because of self-gravity, requiring hypothetical exotic materials or a hollow structure.
Related Questions
What is the common modern estimate for the radius of UY Scuti compared to our Sun?What is the estimated equatorial circumference of UY Scuti?How long would it take light traveling at speed $c$ to circle UY Scuti's circumference?If UY Scuti were to swap places with our Sun, where would its outer boundary potentially reach?Approximately how long would it take the SR-71 Blackbird (cruising at $\approx 3,535 \text{ km/h}$) to circumnavigate UY Scuti?What duration results when calculating the circumnavigation of UY Scuti using the speed of a fast probe, cited at $15 \text{ kilometers per second}$?In which constellation is the hypergiant star UY Scuti located?What is the approximate distance to UY Scuti provided as the primary estimate in light-years?How does the hypothetical lifespan of UY Scuti compare to the projected lifespan of the Sun?Why must the circumnavigation of UY Scuti be treated as a purely geometric calculation of its photosphere perimeter?To achieve travel times to UY Scuti measurable in decades, what speed range would speculative propulsion need to attain?